Background-color problem

[tenors703]

Hi all. I am new to CSS and php and am trying to display a <p> tag with a particular rgb value that I have stored in three variables. However, the background color doesn't change. When I look at the generated HTML it shows that the background-color is actually #26213d52587f even though it was supposed to only use two digits from each value according to my printf... Does anyone know why?

Here's the code:

// these values are actually calculated previously by the code
// but here are their values when it gets to this point.
$secondary_r = 2621;
$secondary_g = 3d52;
$secondary_b = 587f;

// I think this is my problem... am I printing it correctly?
printf( '<STYLE TYPE=\"text/css\"> p {background-color : #%02x%02x%02x;} </STYLE>', $secondary_r, $secondary_g, $secondary_b );

[QuietDean]

Hi, welcome to the forums.

forgive my ignorance, whilst I code php for a living yet I have never used printf

Checking the php.net manual page, I see an example of limitng characters:

printf("[%10.10s]\n", $t); // left-justification but with a cutoff of 10 characters

Have you tried this format?